As I said the idea looks good to me, I just wonder how are we gonna do to fill the levels of the mlm, when I mentioned 3x7 example I meant a downline like in the downline builder.
If we fill the levels each by each (I don't know if this is correct in english) and get into the next once the previous is full we will have a lot of people without referral. It has a advantage and a disadvantage. Let's see
On matrix 2x (2x10, 2x15... 2xn). You (we) will have half (if members are even) or half+1/2 (if members are odd) without referrals if you use the fill full level by level.
Let see:
1
2
4
8
16
32
64
128
256
512
1024
2048
so on...
If we are (example) 26 people interested, we'll fill
1.- 1 / 1 first level (full)
2.- 2 / 2 second level (full)
3.- 4 / 4 third level (full)
4.- 8 / 8 fourth level (full)
5.- 11 / 16 fifth level (not full)
Then, you have three levels with their first level full (first, second and third) wich mean 7 people (1+2+4), in the fourth level you will have 5 people with their first level full (5x2=10) and one person with 1 direct referral (11-10=1). Then you will have 2 people on level fourth without referrals (I wish I could draw this to explain it better... lol).
Finally, you'll have 11 (fifth level) + 2 (fourth level without referrals) equals 13 people without referrals and 1 person with just referral.
What I meant is that if we fill each level step by step once each one is full you will have (in the 2x) half or half+1 of the people without referrals (in 3x forced matrices it's another formula).
Anyway I know a good 2x mlm online company which is offering real product (a good one by the way) and giving away 96% of the coming cash. You may want to check the comission plan at
http://www.ceint.com/rep/peri-tech/opportunity.htmSo, the advantage is that (hopefully we get a "perfect number"(*) of interested people) we can ALL promote the same site with a rotator (I can give the script to the without any cost).
The disadvantage, there will be (at least at the beginning) half or half+1 people without any referral.
I have some other ideas to make it work, I will tell it if we get the group, a very commited group to make this a success.
(*) "perfect numbers" are: 3 (1+2), 7 (1+2+4), 15 (1+2+4+8), 31 (1+2+4+8+16) and so on... P.N.=(2En)-1 with n>=2.
Regards to everyone,
Carlos Ortega.